April 28th, 2011, 07:48 PM
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Originally Posted by EarlyMon
Um. f(x) is literally function of x - and does not mean the variable f is applied to x.
How about functions of the form -
where the last sum is simply the first sum rewritten using the definitions ξn
, and Δξ
.No. In the above example, there is no variable f that is applied to variable x.
The f in f(x) is simply a placeholder - for the operations that are applied to x.
We've been trained to think that way for a reason. Commutation - it comes from commutation notation and means 2*3.
So, by direct evaluation, the equation must become 6/2*3 - as had been said before.
This post makes me realize how much I dislike math. (That is math, right?