Thread: 6÷2(1+2) = ? View Single Post
April 28th, 2011, 08:26 PM   #55 (permalink)
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I GOT IT I GOT I GOT!! xD

I remeber now!!!

I should have known this! I was the only one in my class to get it out of every body!!!

Mr Lars was very proud of me!

It is comming back to me now!

T1 = ax
^2 + bx + c Okay???? You get that???

GOOD

NOW

T1 = 1(1)
^2 + 1(b) + c

but T1 = 1

SO

1 = 1 + b + c

b = - c

NOW

T5 = 1(2)^2 + 2b + c

but T5 = 2

therefore

2 = 4 + 2b + c

therefore

2b = -2 -c

b = -1 - c/2

OKAY now we try simultanous equations!!!

We know that:

b = -1 - c/2

AND

we know that:

b = -c

SO therfore

- c = - 1 - c/2 (that is c divided by 2)

Therefore

-2c = -2 - c

-c = -2

THERFORE

c = 2

NOW we go back to the beginning xP

1 = 1 + b+ c

THERFORE

b = -2

NOW we just do the rest

T6 = 1(6) squared -2 = 2