Thread: 6÷2(1+2) = ? View Single Post
April 29th, 2011, 02:08 AM   #68 (permalink)
alostpacket
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Quote:
 Originally Posted by novox77 If you assume c/2 comes after evaluating (a+b), you are essentially putting (a+b) in the numerator of your division:
Yes

Quote:
 Originally Posted by novox77 c/2 * (a+b)/1 --> c(a+b)/2
EDIT: quoted wrong part should have used this:
Quote:
 c/2(a+b) can only imply that (a+b) is in the denominator without re-writing the equation.
As soon as you've done this part of your calculation you've assumed the order of operations incorrectly.

Think about it this way, 6 over 2 times 3. This is still written correctly, right?

6
__ (3) = 18/2 = 9
2

You would never multiply the (1+2) to the denominator, that would be like buying an iPhone.

 Last edited by alostpacket; April 29th, 2011 at 08:59 AM.