Quote:
Originally Posted by novox77
If you assume c/2 comes after evaluating (a+b), you are essentially putting (a+b) in the numerator of your division:

Yes
Quote:
Originally Posted by novox77
c/2 * (a+b)/1 > c(a+b)/2

EDIT: quoted wrong part should have used this:
Quote:
c/2(a+b) can only imply that (a+b) is in the denominator without rewriting the equation.

As soon as you've done this part of your calculation you've assumed the order of operations incorrectly.
Think about it this way, 6 over 2 times 3. This is still written correctly, right?
6
__ (3) = 18/2 = 9
2
You would never multiply the (1+2) to the denominator, that would be like buying an iPhone.