since we all agree (1+2) must be evaluated first, I'm going to sub in 3 in its place:
6÷2*3
I still don't see how order is irrelevant to the above equation. If I do 2*3 first, the final answer is 1. If I do 6÷2 first, the final answer is 9.
if I convert the division into multiplication, I have to first determine what the divisor is: 2 or the quantity 2*3. Order is irrelevant once everything is converted to multiplication and/or addition, but before that can be done, order IS affecting that conversion...
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