Division must be proven with Multiplication in reverse:
6
÷ 2n = 3/n
3/n * 2n = 6
6
÷ 2n = 3n ?? 3n * 2n = 6n^2
6n
÷ 2n =
(n+n+n+n+n+n)
÷ (n+n) =
[(n+n) (n+n) (n+n)]
÷ (n+n) =
3(n+n)
÷ (n+n) = 3
6n
÷ 2n = 6n
÷ (2n) = 3
obelus is a grouping symbol in itself.
Let n = 2+1. Ans: 1
I am having a hard time finding any references that say 6 / 2n = 3n ....
