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JSONObject optString output

elioncho

Lurker
Nov 12, 2010
3
0
Hello,
I'm receiving a Json response like this:

{"password_confirmation":["is too short (minimum is 4
characters)"],"password":["is too short (minimum is 4
characters)","doesn't match confirmation"],"email":["is too short
(minimum is 6 characters)","should look like an email
address."],"login":["is too short (minimum is 3 characters)","should
use only letters, numbers, spaces, and .-_@ please."]}

I create a JSONObject with the previous string, but when I try to show
the value of a key on my app I'm getting the output with brackets and
quotes.


Code:
HttpResponse mHttpResponse = mHttpClient.execute(mHttpPost); 
 String jsonString = EntityUtils.toString(mHttpResponse.getEntity()); 
      try { 
           JSONObject jsonResponse = new JSONObject(jsonString); 
           login_edit.setError(jsonResponse.optString("login")); 
           }


The optString method returns ["is too short (minimum is 3
characters)","should use only letters, numbers, spaces, and .-_@
please."]. Is this a normal thing or is something wrong in what I'm
doing. Should I just strip brackets and quotes from the string?



Thanks,


El
 

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